-2sin^2x+2-5cosx=0

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Solution for -2sin^2x+2-5cosx=0 equation: 


Simplifying
-2sin2x + 2 + -5cosx = 0

Reorder the terms:
2 + -5cosx + -2in2sx = 0

Solving
2 + -5cosx + -2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -5cosx + -2 + -2in2sx = 0 + -2

Reorder the terms:
2 + -2 + -5cosx + -2in2sx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5cosx + -2in2sx = 0 + -2
-5cosx + -2in2sx = 0 + -2

Combine like terms: 0 + -2 = -2
-5cosx + -2in2sx = -2

Add '2in2sx' to each side of the equation.
-5cosx + -2in2sx + 2in2sx = -2 + 2in2sx

Combine like terms: -2in2sx + 2in2sx = 0
-5cosx + 0 = -2 + 2in2sx
-5cosx = -2 + 2in2sx

Divide each side by '-5osx'.
c = 0.4o-1s-1x-1 + -0.4in2o-1

Simplifying
c = 0.4o-1s-1x-1 + -0.4in2o-1

Reorder the terms:
c = -0.4in2o-1 + 0.4o-1s-1x-1

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